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Starting with the formula for the moment of inertia of a

Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli ISBN: 9780130606204 3

Solution for problem 18PE Chapter 10

Physics: Principles with Applications | 6th Edition

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Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli

Physics: Principles with Applications | 6th Edition

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Problem 18PE

Starting with the formula for the moment of inertia of a rod rotated around an axis through one end perpendicular to its l?engt?h (?I = M ? l2 / 3), prove that the moment of inertia of a rod rotated about an axis through its center perpendicular to its? leng?th is ?I? l2 / 12 . You will find the graphics in Figure 10.12 useful in visualizing these rotations.

Step-by-Step Solution:

Step-by-step solution Step 1 of 2 For the moment of inertia of the rod rotating about an axis through one end perpendicular to its length, Suppose a uniform rod, of mass and length So the mass per unit length of the rod is Take a small element on the rod in between a distance from the center. So the mass of the element is Hence, perpendicular distance of the element from t he center axis is x. So the moment of inertia of this element about the center axis is,

Step 2 of 2

Chapter 10, Problem 18PE is Solved
Textbook: Physics: Principles with Applications
Edition: 6
Author: Douglas C. Giancoli
ISBN: 9780130606204

Since the solution to 18PE from 10 chapter was answered, more than 276 students have viewed the full step-by-step answer. Physics: Principles with Applications was written by and is associated to the ISBN: 9780130606204. This textbook survival guide was created for the textbook: Physics: Principles with Applications, edition: 6. The full step-by-step solution to problem: 18PE from chapter: 10 was answered by , our top Physics solution expert on 03/03/17, 03:53PM. The answer to “Starting with the formula for the moment of inertia of a rod rotated around an axis through one end perpendicular to its l?engt?h (?I = M ? l2 / 3), prove that the moment of inertia of a rod rotated about an axis through its center perpendicular to its? leng?th is ?I? l2 / 12 . You will find the graphics in Figure 10.12 useful in visualizing these rotations.” is broken down into a number of easy to follow steps, and 69 words. This full solution covers the following key subjects: its, perpendicular, rod, rotated, moment. This expansive textbook survival guide covers 35 chapters, and 3914 solutions.

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