What is the change in entropy of 0.130 kg of helium gas at the normal boiling point of helium when it all condenses isothermally to 1.00 L of liquid helium? (?Hint: ?See Table 17.4 in Section 17.6.)
Solution to 28E Step 1 Mass of Helium gas =0.13kg Temperature of Helium gas =4.216K………….(Boiling point of Helium taken from the table) Latent heat of vaporization =20.9x10 J/kg 3 Latent heat of fusion= (-20.9x10 J/kg) Step 2 S=Q/T……………………………………………………..(1) Q=mL f 3 Q= (0.13kg x (-20.9x10 J/kg))
Textbook: University Physics
Author: Hugh D. Young, Roger A. Freedman
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