(a) Calculate the change in entropy when 1.00 kg of water

Solution to 29E Step 1 When the water reaches the boiling point at T=373.15K, it changes into steam and the temperature will keep constant until water is completely transformed into steam. Thus, conversion of water into steam is a isothermal process. Mass of water =1kg 6 Latent heat of vaporization of water =2.256x10 K/kg Step 2 Q=m L v Q=1kg x 2.256x10 K/kg6 Entropy =S S=Q/t 6 S=1 kg x 2.256x10 K/kg/373.15 3 S=6.05x10 J/kg Entropy from Eg 20.5=1.22X10 J/kg3