What is the thermal efficiency of an engine that operates by taking n moles of diatomic ideal gas through the cycle shown in F? ig. P20.38??
Solution 46P Step 1: The process, 1 2 is an isochoric process. Therefore, the work done by the system will be zero. According to ideal gas equation, at point 1, P1 1nRT 1 Where, “n” is the number of moles of the gas P - Pressure at point 1 1 V 1Volume at point 1 R - Universal gas constant T 1Temperature at point 1 T = P V /nR 1 1 1 From the graph, we can see that, P = P and V = V 1 0 1 0 Therefore, T = P V1/nR 0 0 Similarly, T = 2P2 /nR 0 0 The heat change in the system, Q = nC T V Where, C - SpeVfic heat capacity at constant volume T - Change in temperature of the system In process 1 2, T = T - T = 2P V /n2- P 1 /nR = P0V0nR 0 0 0 0 For a diatomic gas, C = 5/2 R V Therefore, Q = n×(5/2)R×P V /nR = 5P V 02 0 0 0
Textbook: University Physics
Author: Hugh D. Young, Roger A. Freedman
The full step-by-step solution to problem: 46P from chapter: 20 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. This textbook survival guide was created for the textbook: University Physics, edition: 13. The answer to “What is the thermal efficiency of an engine that operates by taking n moles of diatomic ideal gas through the cycle shown in F? ig. P20.38??” is broken down into a number of easy to follow steps, and 26 words. This full solution covers the following key subjects: cycle, diatomic, efficiency, engine, gas. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. University Physics was written by and is associated to the ISBN: 9780321675460. Since the solution to 46P from 20 chapter was answered, more than 325 students have viewed the full step-by-step answer.