Four compounds are shown. These compounds react more quickly, or they react with more favorable equilibrium constants, than similar compounds with less conjugated systems. In each case, explain the enhanced reactivity.
Here we have to compare the reactivity of both the compounds.
Here H-A is the general form of an acid. In between this two resonance structures, the 1st resonance structure is aromatic and the second one is nonaromatic .Thus the 1st compound is more stable than the 2nd one because in the 2nd structure the protonation has been carried out on a singly bonded oxygen atom and generate an unstable product whereas in the 1st compound the cation produced is aromatic and resonance stabilized. Thus the 1st compound is more basic than the the second compound.
Textbook: Organic Chemistry
Author: L.G. Wade Jr
Organic Chemistry was written by and is associated to the ISBN: 9780321768414. Since the solution to 29SP from 16 chapter was answered, more than 294 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 29SP from chapter: 16 was answered by , our top Chemistry solution expert on 05/06/17, 06:41PM. This full solution covers the following key subjects: compounds, react, less, constants, enhanced. This expansive textbook survival guide covers 25 chapters, and 1336 solutions. This textbook survival guide was created for the textbook: Organic Chemistry, edition: 8. The answer to “Four compounds are shown. These compounds react more quickly, or they react with more favorable equilibrium constants, than similar compounds with less conjugated systems. In each case, explain the enhanced reactivity.” is broken down into a number of easy to follow steps, and 31 words.