If an n n matrix A is diagonalizable (over R), then there must be a basis of Rn consisting of eigenvectors of A.
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MATH 2450 WEEK 7 Strategy On a close domain, look for all critical points inside the domain. Look for the boundary points then compare. Look for all critical points inside the domain: F = 0 x Fy= 0 Look for all critical points on the boundary g’(t) = 0 Look at the boundary points of the boundary EX. Find the absolute max/min f(x,y) = e(2) - over the disk x + y <= 1 1) x + y < 1 2) x + y = 1 x^(2) - y^(2) Fx= 0 2xe = 0 x = 0 x^(2) - y^(2) Fy= 0 -2ye = 0 y = 0 Po= (0,0) Forms of absolute minimum and maximum 1) Y = sqrt(1-x ) -1<= x <= 1 Y = -sqrt
Textbook: Linear Algebra with Applications
Author: Otto Bretscher
Linear Algebra with Applications was written by and is associated to the ISBN: 9780321796974. Since the solution to 6 from 7 chapter was answered, more than 264 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 6 from chapter: 7 was answered by , our top Math solution expert on 11/15/17, 02:44PM. The answer to “If an n n matrix A is diagonalizable (over R), then there must be a basis of Rn consisting of eigenvectors of A.” is broken down into a number of easy to follow steps, and 23 words. This full solution covers the following key subjects: basis, consisting, diagonalizable, Eigenvectors, Matrix. This expansive textbook survival guide covers 8 chapters, and 441 solutions. This textbook survival guide was created for the textbook: Linear Algebra with Applications, edition: 5.