Solution Found!
A student added 3-phenylpropanoic acid ( PhCH2CH2COOH) to
Chapter 11, Problem 50SP(choose chapter or problem)
A student added 3-phenylpropanoic acid \(\left(\mathrm{PhCH}_{2} \mathrm{CH}_{2} \mathrm{COOH}\right)\) to a molten salt consisting of a 1:1 mixture of \(\text { NaCL }\) and \(A I C L_{3}\) maintained at 170 °C. After 5 minutes, he poured the molten mixture into water and extracted it into dichloromethane. Evaporation of the dichloromethane gave a 96% yield of the product whose spectra follow. The mass spectrum of the product shows a molecular ion at 𝑚/𝑧 132. What is the product?
Equation transcription:
Text transcription:
({PhCH}{2}{CH}{2}{COOH})
A I C L_{3}
{ NaCL }
Questions & Answers
QUESTION:
A student added 3-phenylpropanoic acid \(\left(\mathrm{PhCH}_{2} \mathrm{CH}_{2} \mathrm{COOH}\right)\) to a molten salt consisting of a 1:1 mixture of \(\text { NaCL }\) and \(A I C L_{3}\) maintained at 170 °C. After 5 minutes, he poured the molten mixture into water and extracted it into dichloromethane. Evaporation of the dichloromethane gave a 96% yield of the product whose spectra follow. The mass spectrum of the product shows a molecular ion at 𝑚/𝑧 132. What is the product?
Equation transcription:
Text transcription:
({PhCH}{2}{CH}{2}{COOH})
A I C L_{3}
{ NaCL }
ANSWER:Solution 50SP