Solution Found!
(a) Show how fragmentation occurs to give the base peak at
Chapter 13, Problem 10P(choose chapter or problem)
(a) Show how fragmentation occurs to give the base peak at \(m / z 58\) in the mass spectrum of ethyl propyl amine (N-ethylpropan-1-amine), shown below.
(b) Show how a similar cleavage in the ethyl group gives an ion of \(m / z 72\).
(c) Explain why the peak at \(m / z 72\) is much weaker than the one at \(m / z 58\).
Equation transcription:
Text transcription:
m / z 72
m / z 58
Questions & Answers
QUESTION:
(a) Show how fragmentation occurs to give the base peak at \(m / z 58\) in the mass spectrum of ethyl propyl amine (N-ethylpropan-1-amine), shown below.
(b) Show how a similar cleavage in the ethyl group gives an ion of \(m / z 72\).
(c) Explain why the peak at \(m / z 72\) is much weaker than the one at \(m / z 58\).
Equation transcription:
Text transcription:
m / z 72
m / z 58
ANSWER:Problem 10P
Solution:
Step 1
(a) Fragmentation of ethyl propylamine (N-ethylpropan-1- amine) to give the base peak at m z 58 in the mass spectrum:-
The fragmentation of ethylpropylamine can be carried out as follows to form a base peak at m/z= 58 . The molecular mass of ethylpropylamine is m/z= 87.if we have to form a base peak at m/z 58, i.e 87-58 = 29. The molecular mass of ethyl radical is 29. Thus the fragmented molecules are CH3-CH2-NH-CH2+ (ethyl methylamine free radical)with m/z= 58 and CH3CH2. (ethyl free radical)With m/z 29.
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