For the differential amplifier of Fig. 8.16(a) let I = 0.5 mA, VCC = VEE = 2.5 V, VCM = 1 V, RC = 8 k, and = 100. Assume that the BJTs have vBE = 0.7 V at iC = 1 mA. Find the voltage at the emitters and at the outputs.
1,2 ,…, 1,2,…, 1,2,…, 12 1 4 [2 11 4] 1 3 7 = 5,10,15 )⃗ 1 7 1 4 1 0 1 ⃗ 2 6 4 ] [0 1 ] 1 3 2 2 0 0 0 1 − 2 ⃗⃗⃗ [ 1] 3 − 2 1 1 − 1 = 5 [− ] 2 1 3 2 [2] = 10 2 ] = 15 1 1 10 0 0 0 1 0 0 −2 0 0 −5 0 0 [0 −4 0] [ 0 4] [0 0 −7 0 ] 0 0 5 0 0 0 6 1 0 0 [ 0 0 ] 2 0 0 3 −2 0 (−2) 0 [ 0 4] [ 0 4] 7 2 [−4 1 ] 1 1 5 0 [−1 −2 ] [0 3 ] [2 1 ] −1 −1 1 1 5 0 2 1 [−1 −2][ 0 3][−1 −1 ] 2.5 − 3 5 − 3 [2.3 − 2.5 2.3 − 5] × 0 −1 −1 [ 1 2 1] = 0 = 1 −1 −1 0 0 −1 −1 [ 1 2 1] −1 −1 0 1 0 −1 [0 1 1] 1 0 0 0 {[−1]} 1 −1 −1 −1 [ ] 1 1 1 −1 −1 −1 −1 −1 −1 [ 0 0 0 ] 0 0 0 −1 −1 {[ 1],[ 0]} 0 1 = 1 1 −1 −1 [−1],[1 ] [ 0] 1 0 1 ≤ dim( ) ≤ 1,2,…, ,,…, 0 0 1 [0 2 0 ] [,, 0 0 3 0 0 3 [0 1 0 ] ,,] 0 0 2 1= 0, 2 1, 3 1 0 0 [0 0] 0 0 1 −1 −1 1 [−1 ] 2 [ 1 ] 3 [ 0] 1 0 1 2 3 1 −1 −1 [−1 1 0 ] 1 0 1 1 1 1 [ 1 2 1] −1 −1 0 1 −1 −1 0 0 0 1 1 1 [−1 1 0 ][0 1 0 ][1 2 1] 1 0 1 0 0 1 −1 −1 0
