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(a) Calculate the angular momentum of an ice skater

Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli ISBN: 9780130606204 3

Solution for problem 41PE Chapter 10

Physics: Principles with Applications | 6th Edition

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Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli

Physics: Principles with Applications | 6th Edition

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Problem 41PE

(a) Calculate the angular momentum of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.400 kg ? m2 . (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia if his angular velocity decreases to 1.25 rev/s. (c) Suppose instead he keeps his arms in and allows friction of the ice to slow him to 3.00 rev/s. What average torque was exerted if this takes 15.0 s?

Step-by-Step Solution:

Step-by-step solution Step 1 of 5 The formula for angular momentum of ice skater is, Here, is the angular momentum of the skater, is the moment of inertia of the skater and is the angular velocity. Step 2 of 5 (a) Convert angular velocity in rad/s. The angular momentum of skater is, Substitute for and 37.7 rad/s for . Hence, the angular momentum of the skater is . Step 3 of 5 (b) Convert angular velocity in rad/s. The new moment of inertia is calculated by the angular momentum conservation law as, Here, is the initial moment of inertia of the system, is the final moment of inertia of the system, is the initial angular velocity and is the final angular velocity. Substitute for L and for . Hence, the new moment of inertia is .

Step 4 of 5

Chapter 10, Problem 41PE is Solved
Step 5 of 5

Textbook: Physics: Principles with Applications
Edition: 6
Author: Douglas C. Giancoli
ISBN: 9780130606204

Since the solution to 41PE from 10 chapter was answered, more than 260 students have viewed the full step-by-step answer. This full solution covers the following key subjects: rev, angular, inertia, moment, velocity. This expansive textbook survival guide covers 35 chapters, and 3914 solutions. The answer to “(a) Calculate the angular momentum of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.400 kg ? m2 . (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia if his angular velocity decreases to 1.25 rev/s. (c) Suppose instead he keeps his arms in and allows friction of the ice to slow him to 3.00 rev/s. What average torque was exerted if this takes 15.0 s?” is broken down into a number of easy to follow steps, and 90 words. Physics: Principles with Applications was written by and is associated to the ISBN: 9780130606204. The full step-by-step solution to problem: 41PE from chapter: 10 was answered by , our top Physics solution expert on 03/03/17, 03:53PM. This textbook survival guide was created for the textbook: Physics: Principles with Applications, edition: 6.

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(a) Calculate the angular momentum of an ice skater

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