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Get Full Access to Calculus: Early Transcendentals - 1 Edition - Chapter 9.2 - Problem 66ae
Get Full Access to Calculus: Early Transcendentals - 1 Edition - Chapter 9.2 - Problem 66ae

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# Inverse sine Given the power series for 1 < x < 1, find

ISBN: 9780321570567 2

## Solution for problem 66AE Chapter 9.2

Calculus: Early Transcendentals | 1st Edition

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Problem 66AE

Inverse sine Given the power series

$$\frac{1}{\sqrt{1-x^{2}}}=1+\frac{1}{2} x^{2}+\frac{1 \cdot 3}{2 \cdot 4} x^{4}+\frac{1 \cdot 3 \cdot 5}{2 \cdot 4 \cdot 6} x^{6}+\cdots$$

for -1 < x < 1, find the power series for $$f(x)=\sin ^{-1} x$$ centered at 0.

Step-by-Step Solution:

Solution 66AEStep 1:We know that Integrating the sequence , we getUsing to evaluate C, we getHence the power series for is : .

Step 2 of 1

##### ISBN: 9780321570567

The full step-by-step solution to problem: 66AE from chapter: 9.2 was answered by , our top Calculus solution expert on 03/03/17, 03:45PM. This textbook survival guide was created for the textbook: Calculus: Early Transcendentals, edition: 1. The answer to “?Inverse sine Given the power series$$\frac{1}{\sqrt{1-x^{2}}}=1+\frac{1}{2} x^{2}+\frac{1 \cdot 3}{2 \cdot 4} x^{4}+\frac{1 \cdot 3 \cdot 5}{2 \cdot 4 \cdot 6} x^{6}+\cdots$$for -1 < x < 1, find the power series for $$f(x)=\sin ^{-1} x$$ centered at 0.” is broken down into a number of easy to follow steps, and 37 words. Calculus: Early Transcendentals was written by and is associated to the ISBN: 9780321570567. This full solution covers the following key subjects: power, Series, Centered, Inverse, given. This expansive textbook survival guide covers 112 chapters, and 7700 solutions. Since the solution to 66AE from 9.2 chapter was answered, more than 379 students have viewed the full step-by-step answer.

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