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# Taylor series centered at a 0a. Find the first | Ch 9.3 - 21E ISBN: 9780321570567 2

## Solution for problem 21E Chapter 9.3

Calculus: Early Transcendentals | 1st Edition

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Problem 21E

Taylor series centered at a ? 0a. Find the first four nonzero terms of the Taylor series for the given function centered at a.b. Write the power series using summation notation.f(x) = In x, a= 3

Step-by-Step Solution:

Solution 21EStep 1:a) In this problem we need to find first four nonzero terms of the taylor series for the function f(x) = ln(x) , centered at a = 3 .We know that , the taylor series of the function centered at ‘a’ is : f(x) = f(a) + (x-a)++Given ; f(x) = ln(x), centered at a = 3. f(x) = , then f(3) = ln(3) , then , since (ln(x)) = , then , since = , then = , then ………………Therefore , the taylor series of the function f(x) = ln(x), centered at a = 3is ; f(x) = ln(x) = f(3) +(x-3)++ = ln(3)+ (x-3)++ = ln(3) +(x-3)-+Therefore , the first four nonzero terms of the taylor series centered at ‘3’ for the function ’ are ln(3) +(x-3) -+That is , ln(3) ,(x-3) , -,First term = ln(3)Second term = (x-3)Third term = -Fourth term =

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##### ISBN: 9780321570567

This textbook survival guide was created for the textbook: Calculus: Early Transcendentals, edition: 1. The full step-by-step solution to problem: 21E from chapter: 9.3 was answered by , our top Calculus solution expert on 03/03/17, 03:45PM. The answer to “Taylor series centered at a ? 0a. Find the first four nonzero terms of the Taylor series for the given function centered at a.b. Write the power series using summation notation.f(x) = In x, a= 3” is broken down into a number of easy to follow steps, and 36 words. Calculus: Early Transcendentals was written by and is associated to the ISBN: 9780321570567. Since the solution to 21E from 9.3 chapter was answered, more than 237 students have viewed the full step-by-step answer. This full solution covers the following key subjects: Series, Taylor, Centered, power, nonzero. This expansive textbook survival guide covers 85 chapters, and 5218 solutions.

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