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Repeat P6.91 for the circuit of Figure P6.92. + Vin Vout

Electrical Engineering: Principles & Applications | 6th Edition | ISBN: 9780133116649 | Authors: Allan R. Hambley ISBN: 9780133116649 150

Solution for problem P6.92 Chapter 6

Electrical Engineering: Principles & Applications | 6th Edition

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Electrical Engineering: Principles & Applications | 6th Edition | ISBN: 9780133116649 | Authors: Allan R. Hambley

Electrical Engineering: Principles & Applications | 6th Edition

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Problem P6.92

Repeat P6.91 for the circuit of Figure P6.92. + Vin Vout R1 + R2 C Figure P6.92

Step-by-Step Solution:
Step 1 of 3

PHYSICS 2401 WEEK 8 Chapter 28 DC Circuits Ideal Battery: Remember : Ph= I * R = V /R = V*I Model of non-ideal battery (real life) r = internal resistance ε= open current voltage Isc = ε /r  comes from R = V/I V t I*R =L ε - I*r Battery Pb= P h 2* 2* ε*I = I r + I R * * ε = I r + I RL EX. A battery with ε = 10 V, internal resistance of 1Ώ, connected to R = 4Ώ. Find I. L Pb= P h 2* 2* ε*I = I r + I R I = ε/(r R L I = 10/(1+4) I=2 A EX. A battery connected to a R L,1= 10 Ώ, has V t 35V. When connected to a R L,2= 25Ώ, has V t 39V. Find ε,r. 1 = V/t L,1= 35V/10Ώ = 3.5A 2 = V/t L

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Chapter 6, Problem P6.92 is Solved
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Textbook: Electrical Engineering: Principles & Applications
Edition: 6
Author: Allan R. Hambley
ISBN: 9780133116649

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Repeat P6.91 for the circuit of Figure P6.92. + Vin Vout