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Solved: Approximating definite integrals Use a Taylor

Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett ISBN: 9780321570567 2

Solution for problem 33E Chapter 9.4

Calculus: Early Transcendentals | 1st Edition

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Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

Calculus: Early Transcendentals | 1st Edition

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Problem 33E

Approximating definite integrals Use a Taylor series to approximate the following definite integrals. Retain as many terms as needed to ensure the error is less than 10?4

Step-by-Step Solution:

Solution 33EStep 1:We know the taylor series for is :Using this we get the taylor series for as followsUsing this taylor series we get the taylor series for as follows,Using this in the integral , we get The actual value of the integral is 0.69581.Error = .Hence the value of the integral using taylor series is .

Step 2 of 1

Chapter 9.4, Problem 33E is Solved
Textbook: Calculus: Early Transcendentals
Edition: 1
Author: William L. Briggs, Lyle Cochran, Bernard Gillett
ISBN: 9780321570567

The full step-by-step solution to problem: 33E from chapter: 9.4 was answered by , our top Calculus solution expert on 03/03/17, 03:45PM. This full solution covers the following key subjects: Definite, Integrals, less, ensure, Error. This expansive textbook survival guide covers 85 chapters, and 5218 solutions. This textbook survival guide was created for the textbook: Calculus: Early Transcendentals, edition: 1. The answer to “Approximating definite integrals Use a Taylor series to approximate the following definite integrals. Retain as many terms as needed to ensure the error is less than 10?4” is broken down into a number of easy to follow steps, and 27 words. Calculus: Early Transcendentals was written by and is associated to the ISBN: 9780321570567. Since the solution to 33E from 9.4 chapter was answered, more than 260 students have viewed the full step-by-step answer.

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Solved: Approximating definite integrals Use a Taylor