Elliptic integrals The period of a pendulum is given by

Chapter 8, Problem 71E

(choose chapter or problem)

Elliptic integrals The period of a pendulum is given by

\(T=4 \sqrt{\frac{\ell}{g}} \int_{0}^{\pi / 2} \frac{d \theta}{\sqrt{1-k^{2} \sin ^{2} \theta}} \equiv 4 \sqrt{\frac{\ell}{g}} F(k)\),

where \(\ell\) is the length of the pendulum, \(g \approx 9.8 \quad \mathrm{m} / \mathrm{s}^{2}\) is the acceleration due to gravity, \(k=\sin \left(\theta_{0} / 2\right)\), and \(\theta_{0}\), is the initial angular displacement of the pendulum (in radians). The integral in this formula F(k) is called an elliptic integral and it cannot be evaluated analytically.

a. Approximate F(0.1) by expanding the integrand in a Taylor (binomial) series and integrating term by term.

b. How many terms of the Taylor series do you suggest using to obtain an approximation to F(0.1) with an error less than \(10^{-3}\)?

c. Would you expect to use fewer or more terms (than in part (b)) to approximate F(0.2) to the same accuracy? Explain.