Solved: As two boats approach the marina, the velocity of

Step 1 of 3

Given that,

The velocity of the boat 1 is \(\vec{V}_{1}=0.775 \mathrm{~m} / \mathrm{s}\)

The velocity of boat 1 relative to boat 2 is \(\overrightarrow{V_{12}}=2.15 \mathrm{~m} / \mathrm{s}\)

Using the equation,

\(\overrightarrow{V_{1}}=\overrightarrow{V_{12}}+\overrightarrow{V_{2}} \Rightarrow \overrightarrow{V_{2}}=\overrightarrow{V_{1}}-\overrightarrow{V_{12}}\)

\(\begin{array}{l}
\overrightarrow{V_{2}}=(0.775 \mathrm{~m} / \mathrm{s}) \hat{y}-\left((2.15 \mathrm{~m} / \mathrm{s}) \sin \left(47^{\circ}\right) \hat{x}+(2.15 \mathrm{~m} / \mathrm{s}) \cos \left(47^{\circ}\right) \hat{y}\right) \\
\vec{V}_{2}=(-1.57 \mathrm{~m} / \mathrm{s}) \hat{x}+(-0.691 \mathrm{~m} / \mathrm{s}) \hat{y}
\end{array}\)