A cylinder contains one liter of air at room temperature

Chapter 3, Problem 32P

(choose chapter or problem)

Get Unlimited Answers
QUESTION:

A cylinder contains one liter of air at room temperature (300 K) and atmospheric pressure \(\left(10^{5} \mathrm{~N} / \mathrm{m}^{2}\right)\). At one end of the cylinder is a massless piston, whose surface area is \(0.01 \mathrm{~m}^{2}\). Suppose that you push the piston in very suddenly, exerting a force of 2000 N. The piston moves only one millimeter, before it is stopped by an immovable barrier of some sort.

(a) How much work have you done on this system?

(b) How much heat has been added to the gas?

(c) Assuming that all the energy added goes into the gas (not the piston or cylinder walls), by how much does the internal energy of the gas increase?

(d) Use the thermodynamic identity to calculate the change in the entropy of the gas (once it has again reached equilibrium).

Questions & Answers

QUESTION:

A cylinder contains one liter of air at room temperature (300 K) and atmospheric pressure \(\left(10^{5} \mathrm{~N} / \mathrm{m}^{2}\right)\). At one end of the cylinder is a massless piston, whose surface area is \(0.01 \mathrm{~m}^{2}\). Suppose that you push the piston in very suddenly, exerting a force of 2000 N. The piston moves only one millimeter, before it is stopped by an immovable barrier of some sort.

(a) How much work have you done on this system?

(b) How much heat has been added to the gas?

(c) Assuming that all the energy added goes into the gas (not the piston or cylinder walls), by how much does the internal energy of the gas increase?

(d) Use the thermodynamic identity to calculate the change in the entropy of the gas (once it has again reached equilibrium).

ANSWER:

Step 1 of 5

Part (a)

The work done on the system is given as \(W=F d x\)                                           

For \(F=2000 \mathrm{~N}\) and \(d x=1 \mathrm{~mm}=10^{-3} \mathrm{~m}\).

\(\begin{aligned} W & =(2000)\left(10^{-3}\right) \\ & =2 \mathrm{~J} \end{aligned}\)

Thus, the work done on the system is \(2J\)

 

Add to cart


Study Tools You Might Need

Not The Solution You Need? Search for Your Answer Here:

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back