A test indicates the presence of a particular disease 90%

Chapter 1, Problem 12E

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QUESTION:

PROBLEM 12E

A test indicates the presence of a particular disease 90% of the time when the disease is present and the presence of the disease 2% of the time when the disease is not present. If 0.5% of the population has the disease, calculate the conditional probability that a person selected at random has the disease if the test indicates the presence of the disease.

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QUESTION:

PROBLEM 12E

A test indicates the presence of a particular disease 90% of the time when the disease is present and the presence of the disease 2% of the time when the disease is not present. If 0.5% of the population has the disease, calculate the conditional probability that a person selected at random has the disease if the test indicates the presence of the disease.

ANSWER:

Answer :

Step 1 of 2 :

Given,

A test indicates the presence of a particular disease 90% of the time when the disease is present and the present and the presence of the disease 2% of the time when the disease is not present.

The claim is to find the conditional probability that a person selected at random has the disease if the test indicates the presence of the disease, when 0.5% of the population has the disease.

The probability that the selected person has disease = P(A)

                                                                                    = 0.5%

 

                                                                                    = 0.005

The probability that the selected person does not have  disease = P(B)

                                                                                    = 1 - P(A)

                                                                                    = 1 - 0.005

 

                                                                                    = 0.995.

Let, P(C) be the test indicates the disease

P(C/A) = 90%

           = 0.90

P(C/B) =  2%

           = 0.02

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