Suppose that the percentage of American drivers who are multitaskers (e.g., talk on cell phones, eat a snack, or text message at the same time they are driving) is approximately 80%. In a random sample of n = 20 drivers, let X equal the number of multitaskers.
(a) How is X distributed?
(b) Give the values of the mean, variance, and standard deviation of X.
(c) Find the following probabilities: (i) P(X = 15),
(ii) P(X > 15), and (iii) P(X ≤ 15).
Solution :
Step 1 of 3:
The percentage of american drivers who are multitaskers is approximately 80%. If a random sample of n=20 multitaskers are taken, and X denote the number of multitaskers. We have to find
(a) distribution of X
(b) mean, variance, standard deviation
(c) The probabilities (i) P(X = 15),
(ii) P(X > 15), and (iii) P(X ≤ 15).