Chi-Square Observations: Probability of Exceeding 7.779

Chapter 3, Problem 3.2-17

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QUESTION:

If 15 observations are taken independently from a chi-square distribution with 4 degrees of freedom, find the probability that at most 3 of the 15 observations exceed 7.779.

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QUESTION:

If 15 observations are taken independently from a chi-square distribution with 4 degrees of freedom, find the probability that at most 3 of the 15 observations exceed 7.779.

ANSWER:

Step 1 of 3

From chi-squared table with 4 degrees of freedom,the probability of one exceeding 7.779 is 0.10

p = 0.10 and number of observation is 15.

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Chi-Square Observations: Probability of Exceeding 7.779
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Discover how to compute the likelihood of observations exceeding a certain value in a chi-square distribution with 4 degrees of freedom. Using the binomial distribution formula, evaluate the chances of at most 3 out of 15 observations surpassing the 7.779 mark. Results highlight the intricacies of data distributions.


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