Solution Found!
Chi-Square Observations: Probability of Exceeding 7.779
Chapter 3, Problem 3.2-17(choose chapter or problem)
If 15 observations are taken independently from a chi-square distribution with 4 degrees of freedom, find the probability that at most 3 of the 15 observations exceed 7.779.
Questions & Answers
QUESTION:
If 15 observations are taken independently from a chi-square distribution with 4 degrees of freedom, find the probability that at most 3 of the 15 observations exceed 7.779.
ANSWER:Step 1 of 3
From chi-squared table with 4 degrees of freedom,the probability of one exceeding 7.779 is 0.10
p = 0.10 and number of observation is 15.
Watch The Answer!
Chi-Square Observations: Probability of Exceeding 7.779
Want To Learn More? To watch the entire video and ALL of the videos in the series:
Discover how to compute the likelihood of observations exceeding a certain value in a chi-square distribution with 4 degrees of freedom. Using the binomial distribution formula, evaluate the chances of at most 3 out of 15 observations surpassing the 7.779 mark. Results highlight the intricacies of data distributions.