Solution Found!
Solved: If Z is N(0, 1), find
Chapter 3, Problem 1E(choose chapter or problem)
If \(Z\) is \(N(0,1)\), find
(a) \(P(0.53<Z \leq 2.06)\).
(b) \(P(-0.79 \leq Z<1.52)\).
(c) \(P(Z>-1.77)\).
(d) \(P(Z>2.89)\).
(e) \(P(|Z|<1.96)\).
(f) \(P(|Z|<1)\).
(g) \(P(|Z|<2)\).
(h) \(P(|Z|<3)\).
Equation Transcription:
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Text Transcription:
Z
N(0,1)
P(0.53<Z < or = 2.06)
P(−0.79 < or = Z<1.52)
P(Z>−1.77)
P(Z>2.89)
P(|Z|<1.96)
P(|Z|<1)
P(|Z|<2)
P(|Z|<3
Questions & Answers
QUESTION:
If \(Z\) is \(N(0,1)\), find
(a) \(P(0.53<Z \leq 2.06)\).
(b) \(P(-0.79 \leq Z<1.52)\).
(c) \(P(Z>-1.77)\).
(d) \(P(Z>2.89)\).
(e) \(P(|Z|<1.96)\).
(f) \(P(|Z|<1)\).
(g) \(P(|Z|<2)\).
(h) \(P(|Z|<3)\).
Equation Transcription:
.
.
.
.
.
Text Transcription:
Z
N(0,1)
P(0.53<Z < or = 2.06)
P(−0.79 < or = Z<1.52)
P(Z>−1.77)
P(Z>2.89)
P(|Z|<1.96)
P(|Z|<1)
P(|Z|<2)
P(|Z|<3
ANSWER:Solution :
Step 1 of 3:
If Z is the standard normal distribution N(0,1). We have to find the probabilities.
-
P(0.53<Z
2.06)
-
P(-0.79
- P(Z>-1.77)
- P(Z>2.89)
- P(|Z| >1.96)
- P(|Z|<1)
- P(|Z|<2)
- P((|Z|<3).