Solution Found!
Suppose the birth weight (X) in grams of U.S. infants has
Chapter 3, Problem 19E(choose chapter or problem)
Suppose the birth weight \((X)\) in grams of U.S. infants has an approximate Weibull model with pdf
\(f(x)=\frac{3 x^{2}}{3500^{3}} e^{-(x / 3500)^{3}}, \quad 0<x<\infty\).
Given that a birth weight is greater than \(3000\), what is the conditional probability that it exceeds \(4000\)?
Equation Transcription:
Text Transcription:
(X)
f(x)=3x^2/3500^3 e^-(x/3500)^3, 0<x<
3000
4000
Questions & Answers
QUESTION:
Suppose the birth weight \((X)\) in grams of U.S. infants has an approximate Weibull model with pdf
\(f(x)=\frac{3 x^{2}}{3500^{3}} e^{-(x / 3500)^{3}}, \quad 0<x<\infty\).
Given that a birth weight is greater than \(3000\), what is the conditional probability that it exceeds \(4000\)?
Equation Transcription:
Text Transcription:
(X)
f(x)=3x^2/3500^3 e^-(x/3500)^3, 0<x<
3000
4000
ANSWER:
Step 1 of 2:
Given that X denotes the weight (in grams) of U.S infants. Also it is given that X has an approximate Weibull distribution with probability density function
f(x)=,0<x<
.
We have to find the conditional probability that the birth weight exceeds 4000 grams given that the birth weight is greater than 3000.
That is we have to find P(X>4000|X>3000).