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Calculus / Calculus: Early Transcendentals 1 / Chapter 10.1 / Problem 30E

Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

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Solution: Parametric lines Find the slope of each line and a

Chapter 8, Problem 30E

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QUESTION:

Find the slope of each line and a point on the like. Then graph the line.

x = 1 + 2t/3, y = -4 - 5t/2

Questions & Answers

QUESTION:

Find the slope of each line and a point on the like. Then graph the line.

x = 1 + 2t/3, y = -4 - 5t/2

ANSWER:

Solution 30E

Step 1:

Given parametric lines are; x = 1+ $\frac{2t}{3}$ , y = −4 − $\frac{5t}{2}$ .

In this problem we have to find the slope and a point on the line.

Let us consider two parametric equations ; x = a + bt , y = c + dt.

Then the slope of the line that these two parametric curves define is equal to $\frac{d}{b}$ , and the starting point of the graph of parametric equations of a line will be located at ( t+a , t+c).

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