Solved: In Exercises 3 and 4, determine the measure of the

MATH241 week 5: Partial Derivative Applications Equations of Tangent Planes The equation of the tangent plane of a particular function is z= f ( ,0 +0) x(x0,y 0)(−x +0) x ,y( 0 0)(y−y 0) Where f x f y are the partial derivatives of that function. z=2 ln (y) (1,4) 1. Find the equation of the tangent plane to at Ok, first we need to compute the partial derivatives of this function. f =ln (2)∗2 ln (y) x x 2 f y y And now we need to evaluate the partial derivatives at the given point. f x1,4 =2ln (2)ln 4 ) 1 f y(4 =) 2