Solved: Circles in general Show that the polar equation

Chapter 8, Problem 67E

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QUESTION:

Show that the polar equation

\(r^2-2rr_0 \cos\ (\theta-\theta_0)=R^2-r^2_0\)

describes a circle of radius R whose center has polar coordinates \((r_0,\ \theta_0)\).

Questions & Answers

QUESTION:

Show that the polar equation

\(r^2-2rr_0 \cos\ (\theta-\theta_0)=R^2-r^2_0\)

describes a circle of radius R whose center has polar coordinates \((r_0,\ \theta_0)\).

ANSWER:

Solution 67E
Step 1:

The polar coordinates r and  can be converted to the Cartesian coordinates x and y by using the trigonometric functions sine and cosine:



Given:


      (Using

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