Polar conversion Consider the equation r = 4/(sin ? ? 6 cos ?).a. Convert the equation to Cartesian coordinates and identify the curve it describes.b. Graph the curve and indicate the points that correspond to ? = 0, ?/2, and 2?.c. Give an interval in ? on which the entire curve is generated.

Solution 12REStep-1:1. The objective is to convert the above equation to cartesian coordinates and identify the curve it describes. The relation between cartesian coordinates (x,y) and polar coordinates ( r, is given by , X = r cos( , and Consider , the equation r = That is , r (sin( rsin( By , using the above results we get ; y -6x = 4 Y = 6x+4 Therefore , Y = 6x+4 represents a straight line , here slope is 6 and y intercept is 4.Note ; y = mx +c represents a straight line . Slope is m , and y intercept is c.The graph of y = 6x + 4 is shown below ;