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Get Full Access to Calculus: Early Transcendentals - 1 Edition - Chapter 10.4 - Problem 26e
Get Full Access to Calculus: Early Transcendentals - 1 Edition - Chapter 10.4 - Problem 26e

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# Solved: From graphs to equations Write an equation of the

ISBN: 9780321570567 2

## Solution for problem 26E Chapter 10.4

Calculus: Early Transcendentals | 1st Edition

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Problem 26E

From graphs to equations Write an equation of the following parabolas.

Step-by-Step Solution:

Solution 26EStep 1:In this problem we need to find the equation of parabola .The given graph is ; Definition of parabola ; A parabola is the set of all points in a plane that are equidistant from the focus and the directrix of the parabola.We know that , the equation of the standard parabola with its vertex at ( h , k) that opens downward is ; , where p is used to find the focus and directrix.Where , p is perpendicular distance from vertex to directrix.Therefore , p = =2 , since perpendicular distance from (, ) to ax+by+c =0 is d= .Hence , P= 2, and the given vertex is ( 0 , 2).Therefore , the equation of the standard parabola with its vertex at ( 0 , 2) that opens downward is ; That is , .

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##### ISBN: 9780321570567

This full solution covers the following key subjects: equation, equations, Graphs, parabolas, Write. This expansive textbook survival guide covers 112 chapters, and 5248 solutions. This textbook survival guide was created for the textbook: Calculus: Early Transcendentals, edition: 1. The answer to “From graphs to equations Write an equation of the following parabolas.” is broken down into a number of easy to follow steps, and 11 words. Since the solution to 26E from 10.4 chapter was answered, more than 351 students have viewed the full step-by-step answer. Calculus: Early Transcendentals was written by and is associated to the ISBN: 9780321570567. The full step-by-step solution to problem: 26E from chapter: 10.4 was answered by , our top Calculus solution expert on 03/03/17, 03:45PM.

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