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# Below 0.3 K the slope of the 3He solid-liquid phase ISBN: 9780201380279 40

## Solution for problem 34P Chapter 5

An Introduction to Thermal Physics | 1st Edition

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Problem 34P

Problem 34P

Below 0.3 K the slope of the 3He solid-liquid phase boundary is negative (see Figure 5.13).

(a) Which phase, solid or liquid, is more dense? Which phase has more entropy (per mole)? Explain your reasoning carefully.

(b) Use the third law of thermodynamics to argue that the slope of the phase boundary must go to zero at T = 0. (Note that the 4He solid-liquid phase boundary is essentially horizontal below 1 K.)

(c) Suppose that you compress liquid 3He adiabatically until it becomes a solid. If the temperature just before the phase change is 0.1 K, will the temperature after the phase change be higher or lower? Explain your reasoning carefully.

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Chapter 12 Lecture Notes  Things to remember o Remember that properties of gases can be related by PV=nRT (ideal gas law) o Remember that molecules of gases are far apart, while molecules in liquid and solid are closely packed o Remember that molecules can have polar bonds, due to differences in electronegativity of bonded atoms o Intramolecular bonds are strong  Covalent: 100-400 kJ/mol  Ionic: 700 -1100 kJ/mol o Intramolecular forces: forces holding atoms together to form molecules (covalent bonds, ionic bonds) o Intermolecular forces: electrostatic interactions between molecules that are weaker than forces between oppos

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##### ISBN: 9780201380279

The full step-by-step solution to problem: 34P from chapter: 5 was answered by , our top Physics solution expert on 07/05/17, 04:29AM. This full solution covers the following key subjects: phase, liquid, solid, boundary, below. This expansive textbook survival guide covers 10 chapters, and 454 solutions. An Introduction to Thermal Physics was written by and is associated to the ISBN: 9780201380279. This textbook survival guide was created for the textbook: An Introduction to Thermal Physics , edition: 1. The answer to “Below 0.3 K the slope of the 3He solid-liquid phase boundary is negative (see Figure 5.13).(a) Which phase, solid or liquid, is more dense? Which phase has more entropy (per mole)? Explain your reasoning carefully.________________(b) Use the third law of thermodynamics to argue that the slope of the phase boundary must go to zero at T = 0. (Note that the 4He solid-liquid phase boundary is essentially horizontal below 1 K.)________________(c) Suppose that you compress liquid 3He adiabatically until it becomes a solid. If the temperature just before the phase change is 0.1 K, will the temperature after the phase change be higher or lower? Explain your reasoning carefully.” is broken down into a number of easy to follow steps, and 109 words. Since the solution to 34P from 5 chapter was answered, more than 378 students have viewed the full step-by-step answer.

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Below 0.3 K the slope of the 3He solid-liquid phase