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Get Full Access to Precalculus - 5 Edition - Chapter 2.8 - Problem 98
Get Full Access to Precalculus - 5 Edition - Chapter 2.8 - Problem 98

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# Solve the variation problems in Exercises 9398. | Ch 2.8 - 98

ISBN: 9780321837349 160

## Solution for problem 98 Chapter 2.8

Precalculus | 5th Edition

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Problem 98

Solve the variation problems in Exercises 9398.

Step-by-Step Solution:
Step 1 of 3

Overview week of 9/12/16 3.3 Rules of Differentiation Power of X: d n (n­1) Power Rule: / Xdx= nX Quotient Rule: / f(x)/g(x) = [(f(x) * g(x)) – (f(x) * g(x))] / [g(x)] 2 dx Product Rule: / [dxx) * g(x)] = [f(x) * g’(x)] + [g(x) * f’(x)] Chain Rule: / [dxg(x))] = [f(g(x))]’ * g’(x) Constant Multiple: Power rule d /dx(cf(x)) = c * f ’(x) 3.4 Product and Quotient Rules Product Rule: While [f(x) +/­ g(x)]’ = f ‘(x) +/­ g’(x), The same does not apply to multiplication And division. [f(x)g(x)] ≠ f ‘(x) * g’(x) Instead: [f(x)g(x)] = [f(x) * g’(x)] + [g(x) * f’(x)] Products of multiple functions: (fg)’ = f’g + fg’ (fgh)’ = f’gh + fg’h + fgh’ (fghi)’ = f’ghi + fg’hi + fgh’i + fghi’

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Solve the variation problems in Exercises 9398. | Ch 2.8 - 98