Solution Found!
Let X have the pdf f (x) = xe?x2/2, 0 < x < ?. Find the
Chapter 5, Problem 2E(choose chapter or problem)
QUESTION:
Let X have the pdf \(f(x)=x e^{-x^{2} / 2}, 0<x<\infty\). Find the pdf of \(Y=X^{2}\).
Questions & Answers
QUESTION:
Let X have the pdf \(f(x)=x e^{-x^{2} / 2}, 0<x<\infty\). Find the pdf of \(Y=X^{2}\).
ANSWER:Step 1 of 2
Given:
The probability density function of the random variable X is given as,
\(f\left( x \right) = x{e^{ - \frac{{{x^2}}}{2}}},0 < x < \infty \)
The variable \(Y = {X^2}\).