Let X equal the weight of the soap in a “6-pound” box.
Chapter 5, Problem 4E(choose chapter or problem)
Let \(X\) equal the weight of the soap in a "6-pound" box. Assume that the distribution of \(X\) is \(N(6.05,0.0004)\).
(a) Find \(P(X<6.0171)\).
(b) If nine boxes of soap are selected at random from the production line, find the probability that at most two boxes weigh less than \(6.0171\) pounds each. HINT: Let \(Y\) equal the number of boxes that weigh less than \(6.0171\) pounds.
(c) Let \(\bar{X}\) be the sample mean of the nine boxes. Find \(P(\bar{X} \leq 6.035)\).
Equation Transcription:
.
.
Text Transcription:
X
N(6.05,0.0004)
P(X<6.0171)
6.0171
Y
Bar X
P(bar X < or = 6.035)
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer