Solution Found!
Let X equal the maximal oxygen intake of a human on a
Chapter 5, Problem 7E(choose chapter or problem)
Let \(X\) equal the maximal oxygen intake of a human on a treadmill, where the measurements are in milliliters of oxygen per minute per kilogram of weight. Assume that, for a particular population, the mean of \(X\) is \(\mu=\) \(54.030\) and the standard deviation is \(\sigma=5.8\). Let \(\bar{X}\) be the sample mean of a random sample of size \(n=47\). Find \(P(52.761 \leq \bar{X} \leq 54.453)\), approximately.
Equation Transcription:
Text Transcription:
X
mu= 54.030
sigma=5.8
Bar X
n=47
P(52.761 < or = bar X < or = 54.453)
Questions & Answers
QUESTION:
Let \(X\) equal the maximal oxygen intake of a human on a treadmill, where the measurements are in milliliters of oxygen per minute per kilogram of weight. Assume that, for a particular population, the mean of \(X\) is \(\mu=\) \(54.030\) and the standard deviation is \(\sigma=5.8\). Let \(\bar{X}\) be the sample mean of a random sample of size \(n=47\). Find \(P(52.761 \leq \bar{X} \leq 54.453)\), approximately.
Equation Transcription:
Text Transcription:
X
mu= 54.030
sigma=5.8
Bar X
n=47
P(52.761 < or = bar X < or = 54.453)
ANSWER:Step 1 of 4