Solution Found!
Let X1,X2, . . . ,Xn be a random sample of size n from the
Chapter 7, Problem 14E(choose chapter or problem)
Let \(X_{1}, X_{2^{\prime} \cdots}, X_{n}\) be a random sample of size \(n\) from the normal distribution \(N\left(\mu, \sigma^{2}\right)\) . Calculate the expected length of a confidence interval for \(\mu\), assuming that \(n=5\) and the variance is
(a) known.
(b) unknown.
HINT: To find \(E(S)\), first determine \(E\left[\sqrt{(n-1) S^{2} / \sigma^{2}}\right]\), recalling that \((n-1) S^{2} / \sigma^{2}\) is \(\chi^{2}(n-1)\). (See Exercise 6.4-14.)
Equation Transcription:
Text Transcription:
X_1,X_2,...,X_n
n
N(mu,sigma^2)
mu
n=5
E(S)
E[sqrt(n-1)S^2/sigma^2
(n-1)S2/2
chi^2(n-1)
Questions & Answers
QUESTION:
Let \(X_{1}, X_{2^{\prime} \cdots}, X_{n}\) be a random sample of size \(n\) from the normal distribution \(N\left(\mu, \sigma^{2}\right)\) . Calculate the expected length of a confidence interval for \(\mu\), assuming that \(n=5\) and the variance is
(a) known.
(b) unknown.
HINT: To find \(E(S)\), first determine \(E\left[\sqrt{(n-1) S^{2} / \sigma^{2}}\right]\), recalling that \((n-1) S^{2} / \sigma^{2}\) is \(\chi^{2}(n-1)\). (See Exercise 6.4-14.)
Equation Transcription:
Text Transcription:
X_1,X_2,...,X_n
n
N(mu,sigma^2)
mu
n=5
E(S)
E[sqrt(n-1)S^2/sigma^2
(n-1)S2/2
chi^2(n-1)
ANSWER:
Step 1 of 4
Given,
Sample size,
We have to calculate the expected length of a 95% confidence interval for :