When 12.8 g of Na and 10.2 g of Cl2 react, what is the mass, in grams, of NaCl that is produced?2Na(s) + Cl2(g) ? 2NaCl(s)

Solution 119CQStep 1 of 3:Here, we are asked to find the grams of NaCl produced.Given reaction:2Na(s) + Cl2(g) 2NaCl(s)Given:Mass of Na = 12.8 g Mass of Cl2 = 10.2 g Grams of NaCl =Molar mass of Na = 22.989 g/molMolar mass of S = 70.906 g/molFirst, let’s write the mole-mole factors for the above reaction:2 mol of Na = 2 mol of NaCl. So, the mole-mole factor is: and 1 mol of Cl2 = 2 mol of NaCl. So, the mole-mole factor is: and The mole-mass factor of Na is:1 mol Na = 22.989 g Na. So, the mole-mass factor isand The mole-mass factor of Cl2 is:1 mol Cl2 = 70.906 g. So, the mole-mass factor isand ________________