Solution Found!
(In some of the exercises that follow, we must
Chapter 8, Problem 2E(choose chapter or problem)
Let \(X\) and \(Y\) denote the weights in grams of male and female common gallinules, respectively. Assume that \(X\) is \(N\left(\mu_{X}, \sigma_{X}^{2}\right)\) and \(Y\) is \(N\left(\mu_{Y}, \sigma_{Y}^{2}\right)\).
(a) Given \(n=16\) observations of \(X\) and \(m=13\) observations of \(Y\), define a test statistic and a critical region for testing the null hypothesis \(H_{0}: \mu_{X}=\mu_{Y}\) against the one-sided alternative hypothesis \(H_{1}: \mu_{X}>\mu_{Y}\). Let $\alpha=0.01$. (Assume that the variances are equal.)
(b) Given that \(\bar{x}=415.16, s_{x}^{2}=1356.75, \bar{y}=347.40\), and \(s_{y}^{2}=692.21\), calculate the value of the test statistic and state your conclusion.
(c) Although we assumed that \(\sigma_{X}^{2}=\sigma_{Y}^{2}\), let us say we suspect that that equality is not valid. Thus, use the test proposed by Welch.
Equation Transcription:
Text Transcription:
X
Y
N(mu_X, sigma_X^2)
N(mu_Y, sigma_Y^2)
n=16
m=13
H_0:mu_X=mu_Y
H_1:mu_X>mu_Y
alpha=0.01
Bar x=415.16, s_x^2=1356.75, bar y=347.40
s_y^2=692.21
sigma_X^2=sigma_Y^2
Questions & Answers
QUESTION:
Let \(X\) and \(Y\) denote the weights in grams of male and female common gallinules, respectively. Assume that \(X\) is \(N\left(\mu_{X}, \sigma_{X}^{2}\right)\) and \(Y\) is \(N\left(\mu_{Y}, \sigma_{Y}^{2}\right)\).
(a) Given \(n=16\) observations of \(X\) and \(m=13\) observations of \(Y\), define a test statistic and a critical region for testing the null hypothesis \(H_{0}: \mu_{X}=\mu_{Y}\) against the one-sided alternative hypothesis \(H_{1}: \mu_{X}>\mu_{Y}\). Let $\alpha=0.01$. (Assume that the variances are equal.)
(b) Given that \(\bar{x}=415.16, s_{x}^{2}=1356.75, \bar{y}=347.40\), and \(s_{y}^{2}=692.21\), calculate the value of the test statistic and state your conclusion.
(c) Although we assumed that \(\sigma_{X}^{2}=\sigma_{Y}^{2}\), let us say we suspect that that equality is not valid. Thus, use the test proposed by Welch.
Equation Transcription:
Text Transcription:
X
Y
N(mu_X, sigma_X^2)
N(mu_Y, sigma_Y^2)
n=16
m=13
H_0:mu_X=mu_Y
H_1:mu_X>mu_Y
alpha=0.01
Bar x=415.16, s_x^2=1356.75, bar y=347.40
s_y^2=692.21
sigma_X^2=sigma_Y^2
ANSWER:Step 1 of 6
X represents the weight in grams of male.
Y represents the weight in grams of female.
The variables X and Y are normally distributed.
The number of observations of X is
The number of observations of Y is