Answer: Ammonia and hydrogen chloride react to form solid
Chapter , Problem 123IE(choose chapter or problem)
Ammonia and hydrogen chloride react to form solid ammonium chloride:
\(\mathrm{NH}_{3}(\mathrm{~g})+\mathrm{HCl}(\mathrm{g}) \rightarrow \mathrm{NH}_{4} \mathrm{Cl}(\mathrm{s}\)
Two \(2.00-\mathrm{L}\) flasks at \(25^{\circ} \mathrm{C}\) are connected by a valve, as shown in the drawing on the next page. One flask contains
\(5.00 \mathrm{~g} \text { of } \mathrm{NH}_{3}(\mathrm{~g})\), and the other contains
\(5.00 \mathrm{~g} \text { of } \mathrm{HCl}(\mathrm{g})\). When the valve is opened, the gases react until one is completely consumed.
(a) Which gas will remain in the system after the reaction is complete?
(b) What will be the final pressure of the system after the reaction is complete? (Neglect the volume of the ammonium chloride formed.)
(c) What mass of ammonium chloride will be formed?
Equation Transcription:
Text Transcription:
NH3(g)+HCl(g)NH4Cl(s)
2.00-L
25°C
5.00 g of NH3(g)
5.00 g of HCl(g)
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