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Answer: Gaseous iodine pentafluoride, IF5, can be prepared

Chemistry: The Central Science | 13th Edition | ISBN: 9780321910417 | Authors: Theodore E. Brown; H. Eugene LeMay; Bruce E. Bursten; Catherine Murphy; Patrick Woodward; Matthew E. Stoltzfus ISBN: 9780321910417 77

Solution for problem 127IE Chapter 10

Chemistry: The Central Science | 13th Edition

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Chemistry: The Central Science | 13th Edition | ISBN: 9780321910417 | Authors: Theodore E. Brown; H. Eugene LeMay; Bruce E. Bursten; Catherine Murphy; Patrick Woodward; Matthew E. Stoltzfus

Chemistry: The Central Science | 13th Edition

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Problem 127IE

Gaseous iodine pentafluoride, IF5, can be prepared by the reaction of solid iodine and gaseous fluorine: I2(s) + 5 F2(g)→2 IF5(g)

A 5.00-L flask containing 10.0 g of I2 is charged with 10.0 g of F2, and the reaction proceeds until one of the reagents is completely consumed. After the reaction is complete, the temperature in the flask is 125 °C. (a) What is the partial pressure of IF5 in the flask? (b) What is the mole fraction of IF5 in the flask (c) Draw the Lewis structure of IF5. (d) What is the total mass of reactants and products in the flask?

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PRECALCULUS LINEAR EQUATIONS (IN TWO VARIABLES) The graph of a linearequation is a straight line  SLOPE isthe change in the y variableper unitinthex variable = run  The slope of a line is passing through two1po1nts ( 2 , 2 )and ( X , Y ) ( 1 ,1Y ) 2− 1 = − ( X2, 2 ) 2 1 Negative slope Positive slope  Givenslope “m” and one point onthe line ( X , Y ), the y-intercept is giving by 1 1 = 1− 1  Givenslope “m” and one point onthe line its equationisgiven1by − =1( − ) 2−1  Givenslope “m” and two points on the line its equation − 1 ( by )( − 1) 2−1  Two lines are parallel w1en 2 = m  Two lines are perpendicularw = 1 1 2 EXAMPLE Find the equation of a line passing through (0, 2) which is perpendicular to a line with the equation 6x+4y=8 1) Find the slope of the equation. 6 + 4 = 8 4 = −6 + 8 SLOPE = − + 8 4 4 4 2) For a perpendicular slop =se6 3) Find the y-intercept = 1− 1 4 = 2 − ( ) 0( ) 6 = 2 The equation oftheline is 4 = 6+ 2  When ahorizontalline passing through (0,a) itsequation isy=a  When averticalline ispassing through(a,0)itsequation isx=a

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Chapter 10, Problem 127IE is Solved
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Textbook: Chemistry: The Central Science
Edition: 13
Author: Theodore E. Brown; H. Eugene LeMay; Bruce E. Bursten; Catherine Murphy; Patrick Woodward; Matthew E. Stoltzfus
ISBN: 9780321910417

Since the solution to 127IE from 10 chapter was answered, more than 254 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 127IE from chapter: 10 was answered by , our top Chemistry solution expert on 09/04/17, 09:30PM. This textbook survival guide was created for the textbook: Chemistry: The Central Science, edition: 13. Chemistry: The Central Science was written by and is associated to the ISBN: 9780321910417. The answer to “Gaseous iodine pentafluoride, IF5, can be prepared by the reaction of solid iodine and gaseous fluorine: I2(s) + 5 F2(g)?2 IF5(g)A 5.00-L flask containing 10.0 g of I2 is charged with 10.0 g of F2, and the reaction proceeds until one of the reagents is completely consumed. After the reaction is complete, the temperature in the flask is 125 °C. (a) What is the partial pressure of IF5 in the flask? (b) What is the mole fraction of IF5 in the flask (c) Draw the Lewis structure of IF5. (d) What is the total mass of reactants and products in the flask?” is broken down into a number of easy to follow steps, and 102 words. This full solution covers the following key subjects: . This expansive textbook survival guide covers 305 chapters, and 6352 solutions.

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Answer: Gaseous iodine pentafluoride, IF5, can be prepared