Answer: Intermolecular Forces (Section)Propyl alcohol

Chapter , Problem 24E

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Propyl alcohol \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\right)\) and isopropyl alcohol \({\left[\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHOH}\right]}\), whose space-filling models are shown, have boiling points of \(97.2 \text { and } 82.5^{\circ} \mathrm{C}\), respectively. Explain why the boiling point of propyl alcohol is higher, even though both have the molecular formula, \(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}\).

Equation Transcription:

Text Transcription:

(CH3CH2CH2OH)

[(CH3)2CHOH]

97.2  and  82.5°C

C3H8O

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