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Answer: Enzymes are often described as following the
Chapter , Problem 116AE(choose chapter or problem)
Problem 116AE
Enzymes are often described as following the two-step mechanism:
E + S ⥩ ES (fast)
ES → E + P (slow)
where E = enzyme, S = substrate.
ES = enzyme9substrate complex, and P = product.
(a) If an enzyme follows this mechanism, what rate law is expected for the reaction? (b) Molecules that can bind to the active site of an enzyme but are not converted into product are called enzyme inhibitors. Write an additional elementary step to add into the preceding mechanism to account for the reaction of E with I, an inhibitor.
Questions & Answers
QUESTION:
Problem 116AE
Enzymes are often described as following the two-step mechanism:
E + S ⥩ ES (fast)
ES → E + P (slow)
where E = enzyme, S = substrate.
ES = enzyme9substrate complex, and P = product.
(a) If an enzyme follows this mechanism, what rate law is expected for the reaction? (b) Molecules that can bind to the active site of an enzyme but are not converted into product are called enzyme inhibitors. Write an additional elementary step to add into the preceding mechanism to account for the reaction of E with I, an inhibitor.
ANSWER:Problem 116AEEnzymes are often described as following the two-step mechanism:E + S ES (fast)ES E + P (slow)where E = enzyme, S = substrate.ES = enzyme substrate complex, and P = product.(a) If an enzyme follows this mechanism, what rate law is expected for the reaction (b)Molecules that can bind to the active site of an enzyme but are not converted into product arecalled enzyme inhibitors. Write an additional elementary step to add into the precedingmechanism to account for the reaction of E with I, an inhibitor. Step-by-step solution Step 1 of 3 ^(a)The two-step mechanism for the enzyme reaction is as follows:E + S ES (fast)ES E + P (slow)Here, E is enzyme, S is substrate, ES is enzyme-substrate complex, and P is product. For areaction having multi-steps, the slowest step is the rate determining step. Therefore, the rate ofthe given enzyme reaction is equal to k[ES], where k is rate constant.According to the first step of the mechanism.Rate of forward reaction (R ) For [1[S]Rate of reverse reaction (R Rev = -1[ES]Here, k1- -1are rate constants for forward and reverse reactions of the first step of themechanism.