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The mechanism for the oxidation of HBr by 02 to form 2 H20

Chemistry: The Central Science | 13th Edition | ISBN: 9780321910417 | Authors: Theodore E. Brown; H. Eugene LeMay; Bruce E. Bursten; Catherine Murphy; Patrick Woodward; Matthew E. Stoltzfus ISBN: 9780321910417 77

Solution for problem 121IE Chapter 14

Chemistry: The Central Science | 13th Edition

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Chemistry: The Central Science | 13th Edition | ISBN: 9780321910417 | Authors: Theodore E. Brown; H. Eugene LeMay; Bruce E. Bursten; Catherine Murphy; Patrick Woodward; Matthew E. Stoltzfus

Chemistry: The Central Science | 13th Edition

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Problem 121IE

The mechanism for the oxidation of HBr by 02 to form 2 H20 and Br2 is shown in Exercise, (a) Calculate the overall standard enthalpy change for the reaction process, (b) HBr does not react with 02 at a measurable rate at room temperature under ordinary conditions. What can you infer from this about the magnitude of the activation energy for the rate-determining step? (c) Draw a plausible Lewis structure for the intermediate HOOBr. To what familiar compound of hydrogen and oxygen does it appear similar?

Reaction Mechanisms (Section)

You have studied the gas-phase oxidation of HBr by 02:

4 HBr(g) + 02(g)—2 H20(g) + 2 Br2(g)

You find the reaction to be first order with respect to HBr and first order with respect to 02. You propose the following mechanism:

HBr(g) + 02(g)- HOOBr(g)

HOOBr(g) + HBr(g)—2 HOBr(g)

HOBr(g) + HBr(g)— H20(g) + Br2(g)

(a) Confirm that the elementary reactions add to give the overall reaction, (b) Based on the experimentally determined rate law, which step is rate determining? (c) What are the intermediates in this mechanism? (d) If you are unable to detect HOBr or HOOBr among the products, does this disprove your mechanism?

Step-by-Step Solution:
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Chapter 14, Problem 121IE is Solved
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Textbook: Chemistry: The Central Science
Edition: 13
Author: Theodore E. Brown; H. Eugene LeMay; Bruce E. Bursten; Catherine Murphy; Patrick Woodward; Matthew E. Stoltzfus
ISBN: 9780321910417

The answer to “The mechanism for the oxidation of HBr by 02 to form 2 H20 and Br2 is shown in Exercise, (a) Calculate the overall standard enthalpy change for the reaction process, (b) HBr does not react with 02 at a measurable rate at room temperature under ordinary conditions. What can you infer from this about the magnitude of the activation energy for the rate-determining step? (c) Draw a plausible Lewis structure for the intermediate HOOBr. To what familiar compound of hydrogen and oxygen does it appear similar?Reaction Mechanisms (Section)You have studied the gas-phase oxidation of HBr by 02:4 HBr(g) + 02(g)—2 H20(g) + 2 Br2(g)You find the reaction to be first order with respect to HBr and first order with respect to 02. You propose the following mechanism:HBr(g) + 02(g)- HOOBr(g)HOOBr(g) + HBr(g)—2 HOBr(g)HOBr(g) + HBr(g)— H20(g) + Br2(g)(a) Confirm that the elementary reactions add to give the overall reaction, (b) Based on the experimentally determined rate law, which step is rate determining? (c) What are the intermediates in this mechanism? (d) If you are unable to detect HOBr or HOOBr among the products, does this disprove your mechanism?” is broken down into a number of easy to follow steps, and 188 words. Since the solution to 121IE from 14 chapter was answered, more than 239 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 121IE from chapter: 14 was answered by , our top Chemistry solution expert on 09/04/17, 09:30PM. This textbook survival guide was created for the textbook: Chemistry: The Central Science, edition: 13. This full solution covers the following key subjects: . This expansive textbook survival guide covers 305 chapters, and 6352 solutions. Chemistry: The Central Science was written by and is associated to the ISBN: 9780321910417.

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The mechanism for the oxidation of HBr by 02 to form 2 H20