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Propose a mechanism for the following ring-opening

Chapter 15, Problem 14P

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QUESTION:

Propose a mechanism for the following ring-opening transesterification. Use the mechanism in Problem 21-13 as a model.

\(\mathrm{CH}_{3} \mathrm{OH}\)

\(\mathrm{OCH}_{3}\)

Equation transcription:

Text transcription:

{CH}{3}{OH}

{OCH}{3}

Questions & Answers

QUESTION:

Propose a mechanism for the following ring-opening transesterification. Use the mechanism in Problem 21-13 as a model.

\(\mathrm{CH}_{3} \mathrm{OH}\)

\(\mathrm{OCH}_{3}\)

Equation transcription:

Text transcription:

{CH}{3}{OH}

{OCH}{3}

ANSWER:

Solution:

Here we have to propose a mechanism for the following ring-opening transesterification reaction:-

Step 1

Tetrahydropyran-4-one on reaction with methyl alcohol in acid medium form methyl-4-hydroxybutanoate as the product.

(Tetrahydropyran-4-one)            (Methanol)                (methyl-4-hydroxybutanoate)

Mechanism:

In this mechanism tetrahydropyran-4-one undergoes protonation in presence of an acid and forms an intermediate (3-resonance structures), the most stable intermediate (carbocation) will react with CH3-OH (substitution reaction) and form 2-methoxy-2-hydroxytetrahydropyran, which in presence of an acid again undergoes

protonation and the cleavage of C-O has been carried out with the formation of methyl-4-hydroxybutanoate as the final product.

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