Solved: Determining SpontaneityUse Table to determine
Chapter , Problem 2PE(choose chapter or problem)
Problem 2PE
Determining Spontaneity
Use Table to determine whether the following reactions are spontaneous under standard conditions.
Standard Reduction Potentials in Water at 25 °c | |
E°red(V) |
Reduction Half-Reaction |
+2.87 |
F2(g) + 2 e- → 2F-(aq) |
+1.51 |
MnO4 –(aq) + 8 H+(aq) + 5 e–→.Mn2+(aq) + 4 H2O(l) |
+1.36 |
Cl2(g) + 2 e–.→2 Cl–(aq) |
+1.33 |
Cr2O7 2-(aq) + 14 H+(aq) + 6 e-.→2 Cr3+(aq) + 7 H2O(l) |
+1.23 |
O2(g) + 4 H+(aq) + 4 e–→2 H2O(l) |
+1.06 |
Br2(l) + 2 e–.→2 Br–(aq) |
+0.96 |
NO3 –(aq) + 4 H+(aq) + 3 e–→NO(g) + 2 H2O(l) |
+0.80 |
Ag+(aq) + e–→Ag(s) |
+0.77 |
Fe3+(aq)+ e–→Fe2+(aq) |
+0.68 |
O2(g) + 2 H+(aq) + 2 e–→H2O2(aq) |
+0.59 |
MnO4 –(aq) + 2 H2O(l) + 3 e–→MnO2(s) + 4 OH–(aq) |
+0.54 |
l2(s) + 2 e–.→2 l–(aq) |
+0.40 |
O2(g) + 2 H2O(l)+ 4 e–→4 OH–(aq) |
+0.34 |
Cu2+(aq) + 2 e–.→Cu(s) |
0 [defined] |
2 H+(aq) + 2 e–→H2(g) |
-0.28 |
Ni2+(aq) + 2 e–→Ni(s) |
-0.44 |
Fe2+ (aq) + 2 e–Fe(s) |
-0.76 |
Zn2+(aq) + 2 e–Zn(s) |
-0.83 |
2 H2O(l) + 2 e–→H2(g) + 2 OH–(aq) |
-1.66 |
Al3+(aq) + 3 e–→Al(s) |
-2.71 |
Na+(aq) + e–→Na(s) |
-3.05 |
Li+(aq)+ e–→Li(s) |
(a) Cu(s) + 2 H+(aq)→ Cu2+(aq) + H2(g), (b) Cl2(g) + 2 I-(aq)→ 2 Cl-(aq) + I2(s)
Using the standard reduction potentials listed in Appendix E, determine which of the following reactions are spontaneous under standard conditions:
(a) I2(s) + 5 Cu2+(aq) + 6 H2O(l)→ 2 IO3-(aq) + 5 Cu(s) + 12 H+(aq), (b) Hg2+(aq) + 2 I-(aq)→ Hg(l) + I2(s), (c) H2SO3(aq) + 2 Mn(s) + 4 H+(aq)→ S(s) + 2 Mn2+(aq) + 3 H2O(l)
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