An Olympic-class sprinter starts a race with an

College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs

ISBN: 9781938168000 42

Solution for problem 20PE Chapter 2

College Physics | 1st Edition

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Problem 20PE

An Olympic-class sprinter starts a race with an acceleration of 4.50 m/s2 . (a) What is her speed 2.40 s later? (b) Sketch a graph of her position vs. time for this period.

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Solution 20PE

An Olympic-class sprinter starts a race with an acceleration of 4.50 $m/{s}^{2}.$

a.)Her speed at 2.4 s later can be calculated using the equation ${v={v}_{o}+at}_{\ }$ . Now, ${v}_{o}=0$ , $a=\ 4.50\ m/{s}^{2},t\ =\ 2.4\ s$ . So,

${v={v}_{o}+at}_{\ }$ = ${v=0+(4.50)(2.4)}_{\ }=$ 10.8 $m/s$

b.) A graph of her position vs. time for this period can be plotted as shown below.

Assuming that the acceleration is constant ,the position $x$ is given by the equation $x={x}_{o}+{v}_{o}t+1/2\ a\ {t}^{2}$ . Now, ${x}_{o}=0$ , ${v}_{o}=0$ . So, $x=1/2\ a{t}^{2}$ . Plot of time period vs position is as follows

Time period (in $s)$ Position (in $m)$

0	0
1	2.25
2	9
3	20.25
4	36
5	56.25

Step 2 of 3

Chapter 2, Problem 20PE is Solved

Step 3 of 3

Textbook: College Physics

Edition: 1

Author: Paul Peter Urone, Roger Hinrichs

ISBN: 9781938168000

College Physics was written by and is associated to the ISBN: 9781938168000. The full step-by-step solution to problem: 20PE from chapter: 2 was answered by , our top Physics solution expert on 07/07/17, 04:39PM. This textbook survival guide was created for the textbook: College Physics , edition: 1. The answer to “An Olympic-class sprinter starts a race with an acceleration of 4.50 m/s2 . (a) What is her speed 2.40 s later? (b) Sketch a graph of her position vs. time for this period.” is broken down into a number of easy to follow steps, and 33 words. This full solution covers the following key subjects: acceleration, class, graph, later, olympic. This expansive textbook survival guide covers 34 chapters, and 3125 solutions. Since the solution to 20PE from 2 chapter was answered, more than 2739 students have viewed the full step-by-step answer.

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An Olympic-class sprinter starts a race with an

Solution for problem 20PE Chapter 2

Chapter 2, Problem 20PE is Solved

Textbook: College Physics

Edition: 1

Author: Paul Peter Urone, Roger Hinrichs

ISBN: 9781938168000

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