Problem 20PE
An Olympic-class sprinter starts a race with an acceleration of 4.50 m/s2 . (a) What is her speed 2.40 s later? (b) Sketch a graph of her position vs. time for this period.
Solution 20PE
An Olympic-class sprinter starts a race with an acceleration of 4.50
a.)Her speed at 2.4 s later can be calculated using the equation . Now,
,
. So,
=
10.8
b.) A graph of her position vs. time for this period can be plotted as shown below.
Assuming that the acceleration is constant ,the position is given by the equation
. Now,
,
. So,
. Plot of time period vs position is as follows
Time period (in Position (in
0 |
0 |
1 |
2.25 |
2 |
9 |
3 |
20.25 |
4 |
36 |
5 |
56.25 |