(a) Sketch a graph of velocity versus time corresponding to the graph of displacement versus time given in Figure 2.55. (b) Identify the time or times ( ta , tb , tc , etc.) at which the instantaneous velocity is greatest. (c) At which times is it zero? (d) At which times is it negative?

ANSWER:

Step 1 of 2:-

Here we have to draw the velocity vs time graph and identify the points where the velocity is maximum and zero.

a)

From the curve we can deduce the velocity-time graph by considering the slope of it.

The slope is increasing, decreasing, zero at several places. So, the velocity is also is negative as the slope is negative and high when the slope is more and zero when the slope is zero.

So, the velocity-time graph would look like,

Here the negative velocity shows that the object started moving in the opposite directions.