Solution Found!
In Figure 4.7, the net external force on the 24-kg mower
Chapter 4, Problem 5(choose chapter or problem)
In Figure \(4.7\), the net external force on the \(\text { 24-kg }\) mower is stated to be \(51 \mathrm{~N}\). If the force of friction opposing the motion is \(24 \mathrm{~N}\), what force \(F\) (in newtons) is the person exerting on the mower? Suppose the mower is moving at \(1.5 \mathrm{~m} / \mathrm{s}\) when the force \(F\) is removed. How far will the mower go before stopping?
Equation Transcription:
Text Transcription:
4.7
24-kg
51 N
24 N
F
1.5 m/s
Questions & Answers
QUESTION:
In Figure \(4.7\), the net external force on the \(\text { 24-kg }\) mower is stated to be \(51 \mathrm{~N}\). If the force of friction opposing the motion is \(24 \mathrm{~N}\), what force \(F\) (in newtons) is the person exerting on the mower? Suppose the mower is moving at \(1.5 \mathrm{~m} / \mathrm{s}\) when the force \(F\) is removed. How far will the mower go before stopping?
Equation Transcription:
Text Transcription:
4.7
24-kg
51 N
24 N
F
1.5 m/s
ANSWER:
ANSWER:
Step 1:-
Net force on the mower is,
Mass of the mower is, .
Frictional force acting is, .