×
Log in to StudySoup
Get Full Access to Calculus: Early Transcendentals - 2 Edition - Chapter 6.4 - Problem 4
Join StudySoup for FREE
Get Full Access to Calculus: Early Transcendentals - 2 Edition - Chapter 6.4 - Problem 4

Already have an account? Login here
×
Reset your password

Are shell method integrals easier to evaluate than washer

Calculus: Early Transcendentals | 2nd Edition | ISBN: 9780321947345 | Authors: William L. Briggs ISBN: 9780321947345 167

Solution for problem 4 Chapter 6.4

Calculus: Early Transcendentals | 2nd Edition

  • Textbook Solutions
  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
Calculus: Early Transcendentals | 2nd Edition | ISBN: 9780321947345 | Authors: William L. Briggs

Calculus: Early Transcendentals | 2nd Edition

4 5 1 412 Reviews
17
4
Problem 4

Are shell method integrals easier to evaluate than washer method integrals? Explain. Basic Skills

Step-by-Step Solution:
Step 1 of 3

Calculus notes of 9/26/16 3.11 Related Rates Suppose a spherical weather balloon is filled with gas at a rate of 150 ft /min. What is the rate of change of its radius when the radius is 20 ft We are given / = 150: Volume increases by 150 ft /min. 3 dt dr We want / whedtr = 20 We need an equation relating V to r. 3 For a sphere, V = 4/3ᴨr dv 2 dr Different Rating time / = 4/3dt* 3r / (implicitdtifferentiation) 2 Or V’ = 4/3ᴨ * 3r r’ Solving for / , dt = dt(4ᴨr ) * /2 dvdt = 1/(4ᴨ * 20 ) * 150 = (3/32ᴨ) ft/min = 0.02984 ft/min Procedure: 1. Identify known rates and desired rates. Label what you alread

Step 2 of 3

Chapter 6.4, Problem 4 is Solved
Step 3 of 3

Textbook: Calculus: Early Transcendentals
Edition: 2
Author: William L. Briggs
ISBN: 9780321947345

Other solutions

People also purchased

Related chapters

Unlock Textbook Solution

Enter your email below to unlock your verified solution to:

Are shell method integrals easier to evaluate than washer