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Get Full Access to Calculus: Early Transcendentals - 2 Edition - Chapter 6.4 - Problem 52
Get Full Access to Calculus: Early Transcendentals - 2 Edition - Chapter 6.4 - Problem 52

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# The region bounded by y = 1>1x2 + 12, y = 0, x = 1, and x

ISBN: 9780321947345 167

## Solution for problem 52 Chapter 6.4

Calculus: Early Transcendentals | 2nd Edition

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Problem 52

The region bounded by y = 1>1x2 + 12, y = 0, x = 1, and x = 4 revolved about the y-axis

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Calculus notes for the week of 10/3/16 4.1 Maxima and Minima and 4.2 What Derivatives Tell Us 15 10 5 01 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 -5 -10 -15 f has a local maximum at c if f(c) > f(x) for all x sufficiently close to c. f has a local minimum at c if f(c) < f(x) for all x sufficiently close to c. We see that, if f is differentiable at a local extremum (c), then f’(c) = 0. It is impossible that f is not differentiable at a local extremum. Definition: f has a critical point at x if f ’(x) = 0 or f ’(x) DNE. Coordinates for local extremum will be critical points. We see that, if f ‘(x) is negative on an interval I, then f is decreasing on I. If f ‘(x) is positive on an interval I, then f is

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