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Two children pull a third child on a snow saucer sled

Chapter 4, Problem 31

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QUESTION:

Two children pull a third child on a snow saucer sled exerting forces \(\mathbf{F}_{1}\) and \(\mathbf{F}_{2}\) as shown from above in Figure 4.36. Find the acceleration of the \(49.00-\mathrm{kg}\) sled and child system. Note that the direction of the frictional force is unspecified; it will be in the opposite direction of the sum of \(\mathbf{F}_{1}\) and \(\mathbf{F}_{2}\) .

Figure \(4.36\) An overhead view of the horizontal forces acting on a child’s snow saucer sled.

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QUESTION:

Two children pull a third child on a snow saucer sled exerting forces \(\mathbf{F}_{1}\) and \(\mathbf{F}_{2}\) as shown from above in Figure 4.36. Find the acceleration of the \(49.00-\mathrm{kg}\) sled and child system. Note that the direction of the frictional force is unspecified; it will be in the opposite direction of the sum of \(\mathbf{F}_{1}\) and \(\mathbf{F}_{2}\) .

Figure \(4.36\) An overhead view of the horizontal forces acting on a child’s snow saucer sled.

ANSWER:

Step 1 of 6

Given data:

The sled child system has a mass of  49.00 kg. The diagram is given as,

Step 2 of 6

Force in the  x direction is:

\({F_x} = {F_1}\cos 45^\circ  + {F_2}\cos 30^\circ  \)

Substitute the values in the above expression, and we get,

\({F_x} = 10\cos 45^\circ  + 8\cos 30^\circ \)

\({F_x} = 14\;{\rm{N}}\)

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