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Physics / College Physics 1 / Chapter 4 / Problem 43

College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs

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Integrated Concepts A 35.0-kg dolphin decelerates from

Chapter 4, Problem 43

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QUESTION:

Problem 43PE

Integrated Concepts A 35.0-kg dolphin decelerates from 12.0 to 7.50 m/s in 2.30 s to join another dolphin in play. What average force was exerted to slow him if he was moving horizontally? (The gravitational force is balanced by the buoyant force of the water.)

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QUESTION:

Problem 43PE

Integrated Concepts A 35.0-kg dolphin decelerates from 12.0 to 7.50 m/s in 2.30 s to join another dolphin in play. What average force was exerted to slow him if he was moving horizontally? (The gravitational force is balanced by the buoyant force of the water.)

ANSWER:

Solution 43 PE

The average force exerted to slow down the dolphin can be found using Newton’s second law of motion. Before that we need to find the acceleration of the dolphin (in this case decceleration as dolphin is slowing down).

Step 1 of 2

The dolphin is decelerating from 12.0 m/s to 7.50 m/s in 2.30 s .So the acceleration is given by the ratio of change in velocity to change in time .

$a\ =$ $\frac{\Delta{}v}{\Delta{}t}$

where, $\Delta{}v={v}_{2}-{v}_{1}$ = ( $7.5-12.0$ ) $=-4.5$ m/s

$\Delta{}\ t=$ ${t}_{2}-{t}_{1}=2.1-0=2.1\ s$

So, $a$ = $\frac{-4.5}{2.1}$

= $-$ 2.14 m/s2

$-ve\ sign$ indicates that the dolphin is slowing down.

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