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Integrated Concepts An elevator filled with passengers has

College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs ISBN: 9781938168000 42

Solution for problem 49PE Chapter 4

College Physics | 1st Edition

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College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs

College Physics | 1st Edition

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Problem 49PE

Problem 49PE

Integrated Concepts An elevator filled with passengers has a mass of 1700 kg. (a) The elevator accelerates upward from rest at a rate of 1.20 m/s2 for 1.50 s. Calculate the tension in the cable supporting the elevator. (b) The elevator continues upward at constant velocity for 8.50 s. What is the tension in the cable during this time? (c) The elevator decelerates at a rate of 0.600 m/s2 for 3.00 s. What is the tension in the cable during deceleration? (d) How high has the elevator moved above its original starting point, and what is its final velocity?

Step-by-Step Solution:
Step 1 of 3

STEP 1 OF 8

 a)

pass.png

STEP 2 OF 8

The net force due to tension and weight

Mass of the passengers, m=1700 kg

Acceleration of the elevator(upward)= 

Acceleration due to gravity.g=

We have to find the tension (T)

   

   

   

So, tension in the cable is

STEP 3 OF 8

b)When the velocity is constant , the acceleration ,

   

   

       

So, the tension in the cable is  

STEP 4 OF 8

c)When the elevator deaccelerates downwards

   

       

       

So,tension in the cable

STEP 5 OF 8

d)

d.png

Use  and

For part (a),

STEP 6 OF 8

For part (b),

STEP 7 OF 8

For part ©

STEP 8 0F 8

Now the total distance travelled is

The final velocity at end

Step 2 of 3

Chapter 4, Problem 49PE is Solved
Step 3 of 3

Textbook: College Physics
Edition: 1
Author: Paul Peter Urone, Roger Hinrichs
ISBN: 9781938168000

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Integrated Concepts An elevator filled with passengers has